Отрывок: r r kA r ef r e − σ − σ ′′ ρ = = − ⋅ σ − σ + σ + + σ + σ (19) With disregard for the latter summand, we get the following: 2 1 2 2 2 2 2 2 2 1( 0) ( 2 ) rkA r ef − σ ′′ ρ = = − σ ⋅ σ − + σ , (19а) (0) 0A′′ = , when 1 1.832r ≈ σ , (20) where 1.832 is the root of the equation 1 = (x2+2)e–x2/2. This corresp...
Полная запись метаданных
Поле DC | Значение | Язык |
---|---|---|
dc.contributor.author | Ustinov, A.V. | - |
dc.date.accessioned | 2017-10-25 12:05:17 | - |
dc.date.available | 2017-10-25 12:05:17 | - |
dc.date.issued | 2017-08 | - |
dc.identifier | Dspace\SGAU\20171020\65751 | ru |
dc.identifier.citation | Ustinov AV. Focal-plane field when lighting double-ring phase elements. Computer Optics 2017; 41(4): 515-520. | ru |
dc.identifier.uri | https://dx.doi.org/10.18287/2412-6179-2017-41-4-515-520 | - |
dc.identifier.uri | http://repo.ssau.ru/handle/Zhurnal-Komputernaya-optika/Focalplane-field-when-lighting-doublering-phase-elements-65751 | - |
dc.description.abstract | The focal-plane field amplitude is calculated when lighting double-ring phase elements by flat and Gaussian beams. Emerging conditions in the minimum or maximum centers, including flat-top maxima, are given. For the field amplitude, we obtain equations that define the radius of the first zero-intensity ring based on the deduced expressions. The root values are listed for several parameters of optical elements and incident beams due to the lack of analytical solutions. Numerical simulation results are given for flat incident beams; they are fully consistent with the theoretical calculations. | ru |
dc.description.sponsorship | This work was financially supported by the Russian Foundation for Basic Research (grant No. 16-07-00825). | ru |
dc.language.iso | en | ru |
dc.publisher | Самарский университет | ru |
dc.relation.ispartofseries | 41;4 | - |
dc.subject | phase optical elements | ru |
dc.subject | double-ring phase elements | ru |
dc.subject | focal spot size | ru |
dc.title | Focal-plane field when lighting double-ring phase elements | ru |
dc.type | Article | ru |
dc.textpart | r r kA r ef r e − σ − σ ′′ ρ = = − ⋅ σ − σ + σ + + σ + σ (19) With disregard for the latter summand, we get the following: 2 1 2 2 2 2 2 2 2 1( 0) ( 2 ) rkA r ef − σ ′′ ρ = = − σ ⋅ σ − + σ , (19а) (0) 0A′′ = , when 1 1.832r ≈ σ , (20) where 1.832 is the root of the equation 1 = (x2+2)e–x2/2. This corresp... | - |
dc.classindex.scsti | 29.31.15 | - |
Располагается в коллекциях: | Журнал "Компьютерная оптика" |
Файлы этого ресурса:
Файл | Описание | Размер | Формат | |
---|---|---|---|---|
410408.pdf | 233.98 kB | Adobe PDF | Просмотреть/Открыть |
Показать базовое описание ресурса
Просмотр статистики
Поделиться:
Все ресурсы в архиве электронных ресурсов защищены авторским правом, все права сохранены.